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A milk vendor has 2 cans of milk .The first contains 25% water and the rest milk. The second contains 50% water. How much milk should he mix from each of the container so as to get 12 litres of milk such that the ratio of water to milk is 3:5?
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Milk in 1 litre mixture in 1st can = 3/4 litre. Milk in 1 litre mixture in 2n d can = 1/2 litre. Milk in 1 litre final mixture = 5/8 litre. By rule of alligation we have required ratio 5 : 8
3/4 1/2
\ / (5/8)
/ \
1/8 : 1/8
Therefore ratio of two mixtures: = 18:18 = 1:1
So, quantity of mixture taken from each can, =12×12 =6 litres
Hence, option 3 is the correct answer.
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