A B and C can alone complete a work in 10 12 and 15 days respectively All started the work but B lef...........

Quantitative Aptitude ( CCS) Time and work

A, B and C can alone complete a work in 10, 12 and 15 days respectively. All started the work but B left the work 3 days before completion. How much work was then done by A and B together in the total work?

2/3

3/4

1/3

3/5

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Explanation:

Answer & Explanation
A) 2/3
Explanation:
Let work completed in x days, so A and C worked for all x days, and B for (x-3) days. So
(1/10 + 1/15)*x + (1/12)*(x-3) = 1
Solve, x = 5 days
In 5 days, A did 5/10 = 1/2 of work
In (5-3) = 2 days, B did 2/12 = 1/6 of work
So total by A and B = (1/2 + 1/6) = 2/3

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