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A, B and C can alone complete a work in 10, 12 and 15 days respectively. A and C started the work and after working for 4 days, A left and B joined. In how many days the total work was completed?
6( 5/9) days
6( 2/9 )days
5 (4/9) days
Answer & Explanation
6 2/9 days
(A+C) = (1/10 + 1/15) = 1/6. They worked for 4 days so did (1/6)*4 = 2/3rd of work
Remaining work = 1 – 2/3 = 1/3
Now A left , B and C working
(B+C) = (1/12 + 1/15) = 9/60 = 3/20. They worked for x days and completed 1/3rd of work so (3/20)*x = 1/3, so x = 20/9 days
Total = 4 + 20/9
By: Manpreet kaur ProfileResourcesReport error
answer is 52/9
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