A B and C can all together do piece of work in 10 days in which B takes three times as long as A and...........

Quantitative Aptitude ( CCS) Time and work

A, B and C can all together do piece of work in 10 days, in which B takes three times as long as A and C together do the work and C takes twice as long as A and B together take to do the work. In how many days B can alone do the work?

35 days

33 days

43 days

40 days

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Explanation:

Answer & Explanation
40 days
Explanation:
(A+C) in x days so B completes in 3x days
then (1/x) + (1/3x) = 1/10
solve, x = 40/3
so B in 3x = 3*(40/3)= 40 days
OR
Given A+B+C = 10 and that B takes 3 times as A+C, so A+C is three times stronger than B
So this means that 4 times stronger can do work in 10 days
So 1 time stronger(B) in 4*10 = 40 days

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