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P does half as much work as Q does in 1/5 of the time. Both working together can take 20 days to complete the work. No of days P take to complete the work alone.
28
32
34
35
Answer & Solution Answer – a) 28 Solution: Let Q complete the work in ‘T’ time. In one day, work done by Q is equal to 1/T. In five days, work done by Q is 5/T. It is given that P does half as much work in 1/5 of the time. So P does 1/2 of the work. i.e 5/2T So (1/T + 5/2T) = 1/20. So T = 70. So P takes 2T/5 days. (2*70)/5 = 28days.
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