A can complete a piece of work in 8 days and B can complete the work in 10 days and C in 12 days B a...........

Quantitative Aptitude ( CCS) Time and work

A can complete a piece of work in 8 days and B can complete the work in 10 days and C in 12 days. B and C together worked for 3 days, then C left the work and A replaced him. In how many days will the remaining work be completed ?

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Explanation:

Answer
2
Explanation :
(x-3)/8 + (x/10) + (3/12) = 1
(5x-15+4x)/40 = 1-3/12 = 12-3/12 = 9/12 = ¾
9x – 15 = 3*40/4 = 30
X = 45/9 = 5 (3days completed )
5 -3 = 2 days

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