4 kg of a metal contains 1 5 copper and rest in Zinc Another 5 kg of metal contains 1 6 copper and r...........

Explanation:

Copper in 4 kg = 4/5 kg          

and Zinc in 4 kg = 4 x (4/5) kg

Copper in 5 kg = 5/6 kg        

 and Zinc in 5 kg = 5 x (5/6) kg

Therefore, Copper in mixture = 4/5 + 5/6 = 49/30kg

and  Zinc in the mixture = 16/5 + 25/6 = 221/30kg

Therefore the required ratio = 49 : 221

Hence, option 2 is the correct answer.