Weights of two friends Ram and Shyam are in the ratio 4 5 If Ram 39 s weight is increased by 10 and ...........

Explanation:

Let Syam weight increase by x % and ram's weight and shym's weight is respectively Rand S then given that

R/S=4/5. .....1

R+S+(R+S)15/100=82.8

(R+S)(1+15/100)=82.8

(R+S)(115/100)=82.8

(R+S)= 8280/115..…..2

On solving of eq*1&eq*2

R=32. ,S=40

Putting this value in equition

82.8=R+R10/100+S+SX/100

82.8=32+320/100+40+40x/100

40x/100=82.8-(72+3.2)

2x/5=82.8-75.2

2x/5=7.6

X=38/2=19%

Hence, option 2 is the correct answer.