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A merchant mixes three variants of rice costing Rs.20/kg, Rs.24/kg and Rs.30/kg and sells the mixture at a profit of 20% at Rs.30/kg. How many kg of the second variant will be in the mixture if 2 kgs of the third variant is there in the mixture?
1 kg
5 kgs
3 kgs
6 kgs
Compute cost price of 1 kg of mixture. The selling price of mixture is Rs.30/kg and the merchant makes a profit of 20%. If the cost of 1 kg of the mixture is c, c + 20% of c = 1.2 c = selling price The cost price of the mixture, c = 30/1.2 = Rs.25/kg.
Step 2: Find the ratio in which the 3 variants are mixed The three variants are mixed to obtain a mixture that costs Rs.25 /kg. Variant A costs Rs.20/kg, variant B costs Rs.24/kg and variant C costs Rs.30/kg.
The mean price of the mixture falls between the costs of B and C.
Find out the ratio QA : QC using alligation rule. QA/QC = 30−25/25−20 = 1/1 = 1 : 1 Find out the ratio QB : QC using alligation rule. QB/QC = 30−25/25−24 = 5/1 = 5 : 1 QC is common to both the ratios. The value of QC is found by adding the value of QC = 1 + 1 = 2 Therefore, the required ratio = 1 : 5 : 2 If there are 2 kgs of the third variant in the mixture, then there will be 5 kgs of the second variant in the mixture.
Hence, option 2 is the correct answer.
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