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The sum of length, breadth and height of a room is 19m. The length of the diagonal is 11m. Find he cost of painting the total surface area of the room at the rate of `10 per m2.
240
2400
360
3600
Let length, breadth and height of the room be l, b and h, respectively. Then, l + b + h = 19 … (i) and √(l2+b2+h2 )=11 ⇒l2+b2+h2=121 … (ii) Area of the surface to be painted =2(lb+bh+hl) (l+b+h)2=l2+b2+h2+2(lb+bh+hl) ⇒2(lb+bh+hl)=(19)2-121=361-121=240 Surface area of the room = 240m2 Cost of painting the required area = 10 × 240 = `2400
By: MIRZA SADDAM HUSSAIN ProfileResourcesReport error
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