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A bag contains 600 coins of 25 p denomination and 1200 coins of 50 p denomination. If 12% of 25 p coins and 24% of 50 p coins are removed, the percentage of money removed from the bag is nearly :
21.6%
15.5%
14.3%
12.5%
Total money = Rs.[600*(25/100)+1200*(50/100)]= Rs. 750.
25 paise coins removed = Rs. (600*12/100) = 72.
50 paise coins removed = Rs. (1200*24/100)= 288.
Money removed =Rs.(72*25/100+288*50/100) = Rs.162.
Required percentage = (162/750*100)% = 21.6 %.
Hence, option 1 is the correct answer.
By: Amit Kumar ProfileResourcesReport error
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