send mail to support@abhimanu.com mentioning your email id and mobileno registered with us! if details not recieved
Resend Opt after 60 Sec.
By Loging in you agree to Terms of Services and Privacy Policy
Claim your free MCQ
Please specify
Sorry for the inconvenience but we’re performing some maintenance at the moment. Website can be slow during this phase..
Please verify your mobile number
Login not allowed, Please logout from existing browser
Please update your name
Subscribe to Notifications
Stay updated with the latest Current affairs and other important updates regarding video Lectures, Test Schedules, live sessions etc..
Your Free user account at abhipedia has been created.
Remember, success is a journey, not a destination. Stay motivated and keep moving forward!
Refer & Earn
Enquire Now
My Abhipedia Earning
Kindly Login to view your earning
Support
Type your modal answer and submitt for approval
Two trains are running at 40 km/hr and 20 km/hr respectively in the same direction. If the faster train completely passes a man sitting in the slower train in 5 seconds, the length of the faster train is:
19 metre
27 7/9 metre
13 2/9 meter
33 meter
Relative speed =(40−20) = 20 km/hr =20×5/18 = 50/9 m/s Time =5 seconds Distance = 50/9×5 = 250/9 = 27 7/9 metre ⇒ Length of the faster train =27 7/9 metre
Hence, option 2 is the correct answer.
By: Amit Kumar ProfileResourcesReport error
Access to prime resources
New Courses