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The perimeter of a rectangle is 42 m. If the area of the square formed on the diagonal of the rectangle as its side is 1 1/12 % more than the area of the rectangle, find the longer side of the rectangle.
11 m
16 m
12 m
none of these
Let the sides of the rectangle be l and b respectively. From the given data, √(l2 + b2) = (1 + 1 1/12) lb => l2 + b2 = (1 + 13/12) lb = 25/12 * lb 12(l2+ b2) = 25 lb Adding 24 lb on both sides 12l2+ 12b2+ 24lb = 25 lb12(l2+ b2+ 2lb) = 49 lb12(l + b)2= 49lb but 2(l + b) = 42 => l + b = 21 So 12(21)2= 49lb Solve, we get lb = 108 Since l + b = 21, longer side = 12 m
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