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Abhi invested a certain amount of money in a scheme offering 20% compound interest for two years. Mona invested Rs.1000 more than Abhi in another scheme offering 25% simple interest for two years. Find the amount invested by Abhi if the difference in the interest earned by Abhi and Mona is Rs.1310.
Rs.15600
Let the amount invested by Abhi and Mona be Rs.x and Rs.’x+1000’resp. Interest earned by Abhi = x*{(1+0.20)^3 – 1}= Rs.0.44x Interest earned by Mona = (x+1000)*0.25*2 = Rs.0.5x+500 Now, 0.5x+500 – 0.44x = 1310 => x = Rs.13500
Hence, option 2 is the correct answer.
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