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A person invests some amount at 4% per annum and another amount at 6% per annum. If two-third of the first amount is equal to the one-two of the second amount, and total interest earned in 2 years is Rs. 1080, what was the total sum invested?
Let the first amount be ‘x’ and the second amount be ‘y’
(2/3)*x = (1/2)*y
x = 3/4y
Total interest earned in 2 years = 1080
(x*4*2)/100 + (y*6*2)/100 = 1080
(3/4y*4*2) /100 + (12y)/100=1080
Then , x = 3/4y = 4500
Therefore, total sum invested = 6000+4500 = Rs.10500
Hence, option 1 is the correct answer.
By: Amit Kumar ProfileResourcesReport error
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