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A bottle contains (3/4) of milk and the rest water. How much of the mixture must be taken away and replaced by an equal quantity of water so that the nixtude has half milk and half water?
42(1/4)%
33(1/3)%
22(1/3)%
18(1/2)%
Ratio of milk : water = 3 : 1 water = (1/4)*100 = 25 Let x L is taken out , then qty. of milk left= (3 – 3x/4) water left = (1 – x/4) + x Now , 3 – 3x/4 = (1 – x/4) + x => x = 4/3 Required % = 4/(3*4)*100 = 33(1/3)%
Hence, opton 2 is the correct answer.
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