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There are two mixtures such that they contain 75% milk and 80% milk respectively. Some amount from first mixture is mixed with twice the same amount of second mixture. Find the percentage of milk in the resultant mixture?
75.9%
84.5%
76.3%
78.3%
Let x from first mixture, then 2x form second So milk from first = (75/100)*x, milk from second = (80/100)*2x So milk in resultant mixture is (75x/100) + (160x/100) = 2.35x Total mixture in third is x+2x = 3x So % of milk is (2.35x/3x)*100
Hence, option 4 is the correct answer.
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