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3 containers having capacities in the ratio 2 : 3 : 1 contain mixture of liquids A and B such that the ratio of A to B in them is 2 : 3, 1 : 4 and 3 : 7 respectively. If all the three containers are emptied in a single container, what will be the ratio of A to B in the final mixture?
13 : 58
11 : 54
22: 13
17 : 43
2+3 = 5, 1+4 = 5, 3+ 7 = 10 LCM pf 5, 5, 10 = 10 Capacities are in the ratio 2 : 3 : 1 Suppose the capacities are 20, 30 and 10 So A in final mixture is 2/5 * 20 + 1/5 * 30 + 3/10 * 10 = 17 And B in final mixture is (20+30+10) – 17 = 43 So final ratio = 17 : 43
Hence, option 4 is the correct answer.
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