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A container whose capacity is 60 l contains milk and water in the ratio 3 : 2. How much quantity of the mixture should be replaced with pure milk so that in the final mixture, ratio of milk to water is 7 : 3?
22 l
20 l
15 l
17 l
In 60 l of mixture, milk = 3/5 * 60 = 36 l, so water = 24 l Let x litres of mixture is replaced So Remaining Milk after replacement is = 36 – (3/5)*x + x = 36 + 2x/5 So (36 + 2x/5)/60 = 7/10 Solve, x = 15 l
Hence, option 3 is the correct answer.
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