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Two containers A and B contain mixture of milk and water such that A contains 40% milk and B contains 22% milk. Some part of mixture in container A is replaced by equal quantity of mixture from container B. How much quantity of the mixture was replaced if final mixture contains 32% milk?
3/7
2/5
7/10
5/9
By the method allegation: Reaming……………….Replaced 22………………………….…..40 …………….…..32 8……………………..………..10 So ratio is 8 : 10 = 4 : 5 So replaced part is 5/(4+5) = 5/9
Hence, option 4 is the correct answer.
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