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Container A and B contains 25% and 50% water respectively. The rest is milk in both the containers. How much amount should be mixed from container A to some amount in to some amount of container B so as to get 12 litres of new mixture having water to milk ratio 3 : 5?
6 l
8 l
10 l
7 l
In resultant mixture, water is 3/8 * 100 = 75/2% So by method of allegation: 25%……………………………50% ………………..75/2% 25/2%……………………….25/2% so ratio is 25/2 : 25/2 = 1 : 1 And the total should be 12 l, so 6 l of mixture from A, and 6 l from B.
Hence, option 1 is the correct answer.
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