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From a point C on a level ground, the angle of elevation of the top of a tower is 30 degree. If the tower is 100 meter high, find the distance from point C to the foot of the tower.
170 meter
172 meter
173 meter
167 meter
Let AB be the tower. then∠ACB=30 °AB=100meters AB/AC=tan30 =>100/AC=1/√3 =>AC=√3∗100 =>AC=1.73∗100 =>AC=173meter Please always remember the value of square root 3 is 1.73, and value of square root 2 is 1.41.
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