Find the angle of elevation of the sun when the shadow of a pole of 18 m height is 6 radic 3m long ........

Explanation:

Let RQ be the pole and PQ be the shadow 
Given that RQ = 18 m and PQ=6√3m
Let the angle of elevation, angleRPQ = θ 
From the right  PQR, 
tanθ=RQ/PQ=18/6√3=3/√3=√3
⇒θ=1/tan(√3)=60°