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I forgot the last digit of a 7-digit telephone number. If 1 randomly dial the final 3 digits after correctly dialing the first four, then what is the chance of dialing the correct number?
1/1000
1/999
1/10000
1/9999
It is given that last three digits are randomly dialled.
Then each of the digit can be selected out of 10 digits in 10 ways. Hence required probability =(1/10)3 = 1/1000
Hence, option 1 is the correct answer.
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Noorbir Singh
pls explain if possible?
Atika
explanation not clear
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