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Three houses are available in a locality. Three persons apply for the houses. Each applies for one house without consulting others. The probability that all the three apply for the same house is :
2/9
1/9
8/9
7/9
One person can select one house out of 3= 3C1ways = 3.
Hence, three persons can select one house out of 3 in 3 x 3 x 3 =27
Therefore, probability that all thre apply for the same house is 3/27=1/9
Hence, option 2 is the correct answer.
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