An observer 2 m tall is 10 radic 3m away from a tower The angle of elevation from his eye to the top...........

Quantitative Aptitude ( CCS) Trignometry

An observer 2 m tall is 10√3m away from a tower. The angle of elevation from his eye to the top of the tower is 30º. The height of the tower is:

11 m

13 m

12 m

14 m

SR = PQ = 2 m
PS = QR=10√3m
tan30°=TS/PS
1/√3=TS/10√3
TS=10√3/√3=10m
TR = TS + SR = 10 + 2 = 12 m

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