In a box there are 8 red 7 blue and 6 green balls One ball is picked up randomly What is the probabi......

In a box, there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green?

Total number of balls = (8 + 7 + 6) = 21.

Let E = event that the ball drawn is neither red nor green 

=event that the ball drawn is blue.

n(E) = 7.

P(E) = n(E)/n(S) = 7/21 = 1/3.

Hence, option 1 is the correct answer.

By: Amit Kumar