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A word consists of 9 letters; 5 consonants and 4 vowels.Three letters are choosen at random. What is the probability that more than one vowel will be selected ?
3 letters can be choosen out of 9 letters in 9C3 ways.
More than one vowels ( 2 vowels + 1 consonant or 3 vowels ) can be choosen in (4C2*5C1)+4C3 ways
Hence,required probability = (4C2*5C1)+4C3 /9C3 = 17/42
Hence, option 2 is the correct answer.
By: Amit Kumar ProfileResourcesReport error
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