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A speaks truth in 75% of cases and B in 80% of cases. In what percentage of cases are they likely to contradict each other, narrating the same incident
Let A = Event that A speaks the truth
B = Event that B speaks the truth
Then P(A) = 75/100 = 3/4
P(B) = 80/100 = 4/5
P(A-lie) = 1−3/4 = 1/4
P(B-lie) = 1−4/5 = 1/5
Now, A and B contradict each other =[A lies and B true] or [B true and B lies]
= P(A).P(B-lie) + P(A-lie).P(B)
(3/5 x 1/5) + (1/4 x 4/5) = 7/20
(7/20 x 100) = 35%
Hence, option 1 is the correct answer.
By: Amit Kumar ProfileResourcesReport error
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