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A train travels 360 km at a uniform speed. If the speed had been 5 km/h more, it would have taken 1 hour less for the same journey. Find the speed of the train?
42 kmh
43 kmh
45 kmh
40 kmh
We know that, Speed = Distance/time
Let the speed of the train be = x kmph NORMAL SPEED SPEED 5 KMPH MORE Distance = 360 Km Distance =360 speed = X Kmph Speed = (x+5) Time =360/X Time =360/(x+15)
For the same journey if the speed increased 10 kmph more it will take 1 hour less Time with original speed - time with increased speed = 1 (360/x) - (360/x+10) = 1 (360(x+5)-360x)/x(x+5) =1 360X + 1800 -360X = X(X+5) X^2 + 5x - 1800 = 0 X = 40 or -45 X cannot be negetive value
X = 40 kmph.
Hence, option 4 is the correct answer.
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