The Top of a 15 metre high tower makes an angle of elevation of 60 degree with the bottom of an elec...........

Explanation:

Let AB be the tower and CD be the electric pole.
∠ACB=60°,∠EDB=30°,
AB=15
Let CD=h then
BE=AB−AE=AB−AE=15−h
AB/AC=tan60°=√3
=>AC=AB/√3
=>AC=15/√3 and,=>DE=(BE∗√3)=√3(15−h)
Now,AC=DE
=>15√3=√3(15−h)
=>3h=45−15
=>h=303=10mm