The Top of a 15 metre high tower makes an angle of elevation of 60 degree with the bottom of an elec......

The Top of a 15 metre high tower makes an angle of elevation of 60 degree with the bottom of an electric pole and angle of elevation of 30 degree with the top of pole. Find the height of the electric pole.

Let AB be the tower and CD be the electric pole.
∠ACB=60°,∠EDB=30°,
AB=15
Let CD=h then
BE=AB−AE=AB−AE=15−h
AB/AC=tan60°=√3
=>AC=AB/√3
=>AC=15/√3 and,=>DE=(BE∗√3)=√3(15−h)
Now,AC=DE
=>15√3=√3(15−h)
=>3h=45−15
=>h=303=10mm

By: MIRZA SADDAM HUSSAIN