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A train travelling with a speed of 60 km/hr catches another train travelling in the same direction and then leaves it 120m behind in 18 seconds. The speed of the second train is
42kmph
72kmph
36kmph
44kmph
Given speed of the first train = 60 km/hr = 60 x 5/18 = 50/3 m/s
Let the speed of the second train = x m/s
Then, the difference in the speed is given by
50/3 − x = 120/18
=> x = 10 m/s
=> 10 x 18/5 = 36 km/hr
Hence, option 3 is the correct answer.
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