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A train moves past a telegraph post and a bridge 264 m long in 8 seconds and 20 seconds respectively. What is the speed of the train ?
79.2 km/hr
80 km/hr
69.2 km/hr.
82 km/hr.
Let the length of the train be x metres and its speed by y m/sec. Then, x/y = 8 => x = 8y Now, (x+264)/20 = y 8y + 264 = 20y y = 22. Speed = 22 m/sec = (22*18/5) km/hr = 79.2 km/hr.
Hence, option 1 is the correct answer.
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