A bag contains red blue and green balls in the ratio of 3 5 4 resp 10 pink balls are put in the bag ...........

Quantitative Aptitude ( CCS) Probability

A bag contains red, blue and green balls in the ratio of 3:5:4 resp. 10 pink balls are put in the bag and two balls are randomly drawn from the bag. The probability that one ball is green and other is red is 20/161. Find the difference in the number of green and red balls in the bag.

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Explanation:

Probability that one ball is red and other is green
= (3xC1*4xC1)/ (12x+10)C2 = 20/161
=> 246x^2 – 1140x – 450 = 0
=> 41x^2 – 190x – 75 = 0
=> x = 5, -15/41
Bag contains 10 pink, 15 red , 25 blue and 20 green balls.
Difference in the number of green and red balls = 20 – 15 = 5

Hence, option 1 is the correct answer.

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