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In a party there are 6 couples. Out of them 5 people are chosen at random. Find the probability that there are at the least two couples ?
4/33
8/25
5/33
6/21
Number of ways of (selecting at least two couples among five people selected) = 6C2*8C1 As remaining person can be any one among three couples left. Required probability = 6C2*8C1/12C5 = 5/33.
Hence, option 3 is the correct answer.
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