The probability of success of three students A B and C in the one examination are 1 5 1 4 and 1 3 re...........

Quantitative Aptitude ( CCS) Probability

The probability of success of three students A, B and C in the one examination are 1/5, 1/4 and 1/3 respectively. Find the probability of success of at least two.

2/3

2/6

1/6

1/3

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Explanation:

P(A)=1/5, P(B)=1/4, P(C)=1/3
Required probability
[ P(A)P(B){1−P(C)} ] + [ {1−P(A)}P(B)P(C) ] + [ P(A)P(C){1−P(B)} ] + P(A)P(B)P(C)
= [1/4*1/3*4/5] + [3/4*1/3*1/5] + [2/3*1/4*1/5] + [1/4*1/3*1/5]
=4/60 + 3/60 + 2/60 + 1/60 ==>10/60=1/6.

Hence, option 2 is the correct answer.