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A bag contain 6 green and 9 yellow flowers. Two successive drawing of four flowers are made such that the flowers are not replaced before the second draw. find the probability that the first draw gives 4 green flowers and second draw gives 4 yellow flowers.
16/97
8/453
3/715
5/715
In 1st draw 4 green flowers selected then P=6C4/15C4 =15/1365=1/91 In 2nd draw 4 yellow flowers selected then P=9C4/11C4 =126/330=21/55 The required probability=1/91*21/55=3/715
Hence, option 3 is the correct answer.
By: Amit Kumar ProfileResourcesReport error
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