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Two Persons attend an interview for two vacancies. The probability of 1st person selection is (1/4) and the probability of 2nd person selection is (1/6). What is the probability that only one of them is selected ?
1/4
2/7
4/5
1/3
Give chance for 1st and 2nd person get selected is 1/4 and 1/6 1st person not get selected chance is (1-1/4)=3/4 2nd person not get selected chance is (1-1/6)=5/6 P(only one get selected)=P(1st selected and 2nd not selected) + P(1st not selected and 2nd selected) =(1/4*5/6) + (3/4*1/6) =8/24=1/3
Hence, option 4 is the correct answer.
By: Amit Kumar ProfileResourcesReport error
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