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A bag contains 8 apple and 6 orange. Four fruits are drawn out one by one and not replaced. What is the probability that they are alternatively of different fruits?
10/143
15/120
20/143
26/110
Fruits can be drawn in two format AOAO and OAOA Apple drawn 1st P=8/14*6/13*7/12*5/11 Orange drawn 1st P=6/14*8/13*5/12*7/11 Adding both we get 2[8*7*6*5/14*13*12*11]=2*(10/143)=20/143.
Hence, option 3 is the correct answer.
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