send mail to support@abhimanu.com mentioning your email id and mobileno registered with us! if details not recieved
Resend Opt after 60 Sec.
By Loging in you agree to Terms of Services and Privacy Policy
Claim your free MCQ
Please specify
Sorry for the inconvenience but we’re performing some maintenance at the moment. Website can be slow during this phase..
Please verify your mobile number
Login not allowed, Please logout from existing browser
Please update your name
Subscribe to Notifications
Stay updated with the latest Current affairs and other important updates regarding video Lectures, Test Schedules, live sessions etc..
Your Free user account at abhipedia has been created.
Remember, success is a journey, not a destination. Stay motivated and keep moving forward!
Refer & Earn
Enquire Now
My Abhipedia Earning
Kindly Login to view your earning
Support
Type your modal answer and submitt for approval
Directions : There are 3 people – A, B and C. Probability that A speaks truth is 3/10, probability that B speaks truth is 3/7 and probability that C speaks truth is 5/6. For a particular question asked, at most 2 people speak truth. All people answer to a particular question asked.
What is the probability that B will speak truth for a particular question asked?
7/18
14/33
4/15
9/28
n any case B speaks truth. Now at most 2 people speak truth for 1 question So case 1: B and A speaks truth Probability = 3/7 * 3/10 * (1-5/6) = 3/140 Case 2: B and C speaks truth Probability = 3/7 * ( 1- 3/10) * 5/6 = 5/20 Case 3: Only B speaks truth Probability = 3/7 * ( 1- 3/10) * (1-5/6) = 1/20 Add the three cases = 6/20 + 3/140 = 45/140 = 9/28
Hence, option 4 is the correct answer.
By: Amit Kumar ProfileResourcesReport error
Access to prime resources
New Courses