Some green balls are transferred from bag 1 to bag 3 Now probability of choosing a blue ball from ba...........

Quantitative Aptitude ( CCS) Probability

Directions : There are 3 bags containing 3 colored balls – Red, Green and Yellow.
Bag 1 contains:
24 green balls. Red balls are 4 more than blue balls. Probability of selecting 1 red ball is 4/13

Bag 2 contains:
Total balls are 8 more than 7/13 of balls in bag 1. Probability of selecting 1 red ball is 1/3. The ratio of green balls to blue balls is 1 : 2

Bag 3 contains:
Red balls equal total number of green and blue balls in bag 2. Green balls equal total number of green and red balls in bag 2. Probability of selecting 1 blue ball is 3/14.

Some green balls are transferred from bag 1 to bag 3. Now probability of choosing a blue ball from bag 3 becomes 3/16. Find the number of remaining balls in bag 1.

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Explanation:

blue balls in bag 3 are 12
Let x green balls are transferred. So
12/(56+x) = 3/16 [56 was number of bags in bag 3 before transfer] Solve, x = 8
So remaining number of balls in bag 1 = 52-8 = 44\

Hence, option 4 is the correct answer.