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A bag contains 4 white and 5 blue balls. Another bag contains 5 white and 7 blue balls. What is the probability of choosing two balls such that one is white and the other is blue?
61/110
59/108
45/134
53/108
Case 1: Ball from first bag is white, from another is blue So probability = 4/9 * 7/12 = 28/108 Case 1: Ball from first bag is blue, from another is white So probability = 5/9 * 5/12 = 25/108 Add the cases So required probability = 28/108 + 25/108 = 53/108
Hence, option 4 is the correct answer.
By: Amit Kumar ProfileResourcesReport error
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