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There are 150 tickets in a box numbered 1 to 150. What is the probability of choosing a ticket which has a number a multiple of 3 or 7?
52/125
53/150
37/150
32/75
Multiples of 3 up to 150 = 150/3 = 50 Multiples of 7 up to 150 = 150/7 = 21 (take only whole number before the decimal part) Multiples of 21 (3×7) up to 150 = 150/21 = 7 So total such numbers are = 50 + 21 – 7 = 64 So required probability = 64/150 = 32/75
Hence, option 4 is the correct answer.
By: Amit Kumar ProfileResourcesReport error
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