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In a 250 liter of a mixture of Milk and Water, Water is X%. The milkman sold 50 liters of the mixture and replaced same quantity with water. If the percent of Milk in final mixture is 64%, then what is the percentage of Milk in the initial mixture?
20%
40%
50%
80%
Milk = 250*(100-x/100) 50 liters replaced then 250*(100-x/100) – 50*(100-x/100) = 64% of 250 X = 20% Milk = 80%
By: Pranav Gupta ProfileResourcesReport error
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