There are 4 green and 5 red balls in first bag And 3 green and 5 red balls in second bag One ball is...........

Quantitative Aptitude ( CCS) Probability

There are 4 green and 5 red balls in first bag. And 3 green and 5 red balls in second bag. One ball is drawn from each bag. What is the probability that one ball will be green and other red?

33/72

37/72

35/72

39/72

छोटे Courses बड़े Results

Master Probability

Prepare through Micro-courses

Try Now

Explanation:

Case 1:first green, second red
Prob. = 4/9 × 5/8 = 20/72
Case 2:first red, second green
Prob. = 5/9 × 3/8 = 15/72
Add the two cases
=20/72+15/72=35/72

Report error

Submit Error