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A cistern filled in 20 hours by three pipes A, B and C. The pipe C is twice as fast as B and B is thrice as fast as A. How much time will pipe A alone take to fill the tank?
205
252
200
none of these
Suppose pipe A alone takes x hours to fill the tank. Then pipes B and C will take x/3 and x/6 hours respectively to fill the tank. Therefore 1/x + 3/x + 6/x= 1/20 ⇒ 10/x = 1/20 ⇒ x = 200hrs
By: MIRZA SADDAM HUSSAIN ProfileResourcesReport error
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