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Pipe P and Q running together can fill a cistern in 6 minutes. If P takes 5 minutes less than Q to fill the cistern, then the time in which Q alone can fill the cistern will be
10min
15min
30min
25min
Let pipe P fills the cistern in x minutes. Therefore, pipe Q will fill the cistern in (x+5) minutes. Now, 1/x + 1/(x+5) = 1/6 → x = 10 Thus, the pipe P can fill in 10 minutes, so Q can fill in 10+5 =15 minutes.
By: MIRZA SADDAM HUSSAIN ProfileResourcesReport error
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