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A 4 digit number which when divided by 12, 16 and 18 gives out a common remainder i.e. 21. Find the smallest/ least such number.
1547
1461
1465
1265
Here least possible 4 digit number is needed that means we need the LCM We must first find LCM of 12, 16, 18 and 20 ∴ LCM = 720 Now this is a 3 digit number. If we multiply it by 2 we get (720 x 2) = 1440 → (4 digit number) But 1440 is divisible by 12, 16, 18 and 20 We must have 21 as remainder, as per given condition. So, Number = 1440 + 21 = 1461
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