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Pipes A, B and C which fill the tank together in 6 hours are opened for 2 hours after which pipe C was closed. Find the number of hours taken by pipe C to fill the tank if the remaining tank is filled in 7 hours ?
16
14
20
22
Answer & Explanation 14 Explanation: 1/A + 1/B + 1/C = 1/6 Now given that first all open for 2 hours, then C closed and A+B completes in 7 hours, so (1/A + 1/B + 1/C) *2 + (1/A + 1/B)*7 = 1 Put 1/A + 1/B = 1/6 – 1/C (1/6 – 1/C + 1/C) *2 + (1/6 – 1/C)*7 = 1 2/6 + 7/6 – 7/C = 1 Solve, C = 14
By: Sandeep Dubey ProfileResourcesReport error
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