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A can contains a mixture of two liquids A and B in the ratio 9:7 when 8 liters of mixture are drawn off and the can is filled with B,the ratio of A and B becomes 9:8.How many liters of liquid A was contained by the can initially?
70.5 litres
63 litres
76.5 litres
82.5 litres
Initial = 9x and 7x Quantity of A in mixture left = (9x- (9/16)*8) = 9x – (9/2) Quantity of B in mixture left = (7x – (7/16)*8) = 7x – (7/2) [9x – (9/2)]/[7x – (7/2)+8] = 9/8 18x-9/14x + 9 = 9/8 144x-72 = 126x+81 18x=153 X = 153/18 = 8.5 9x = 9*8.5 = 76.5litre
By: Pranav Gupta ProfileResourcesReport error
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